- C Program To Count Repeated Character In A Strings
- C Program To Count Repeated Character In A String
- C Program To Count Number Of Same Characters In A String
- Count Repeated Character In A Cell
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Write a c program to count occurrences of a word in a string. Logic to count occurrences of a word in a string. Word count program. We will learn program that is to count the occurrences of particular word on to the string given, count occurrences of a word in a string. I have been implemnting an algorithim for counting and printing duplicate letters (two times or more) in a C string. Example: If input string was: 'Hello There' The output should be: e - 3 h.
I have been implemnting an algorithim for counting and printing duplicate letters (two times or more) in a C string.
Example :If input string was :
'Hello There'
The output should be : https://treesecurity491.weebly.com/blum-dynalog-free-download.html.My current code has been printing what i need,but it doesn't consider capital letters, it also keep giving me the message
usr2564301stack smashing detected (core dumped)
. So, it doesn't work properly and I'm not sure why :18.3k77 gold badges3535 silver badges7777 bronze badges
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1 Answer
Download film animasi saint seiya subtilite indonesia full episode.
'Hello There'
doesn't fit in a character array of size 10
. This is good example of why you should not use gets
.Use:
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Given a string, find the repeated character present first in the string.
(Not the first repeated character, found here.)
Examples:
Examples:
Asked in: Goldman Sachs internship
Simple Solution using O(N^2) complexity
The solution is to loop through the string for each character and search for the same in the rest of the string. This would need two loops and thus not optimal.
The solution is to loop through the string for each character and search for the same in the rest of the string. This would need two loops and thus not optimal.
C Program To Count Repeated Character In A Strings
C++
// character that is repeated #include <string.h> using namespace std; { int p = -1, i, j; { { { break ; } break ; } // Driver code { int pos = findRepeatFirstN2(str); cout << 'Not found' ; cout << str[pos]; } // This code is contributed |
C
// is repeated #include <string.h> int findRepeatFirstN2( char * s) // this is O(N^2) method for (i = 0; i < strlen (s); i++) { if (s[i] s[j]) { break ; } break ; } // Driver code { int pos = findRepeatFirstN2(str); printf ( 'Not found' ); printf ( '%c' , str[pos]); } |
Java
// that is repeated import java.util.*; class GFG { static int findRepeatFirstN2(String s) int p = - 1 , i, j; { { { break ; } break ; } // Driver code { int pos = findRepeatFirstN2(str); if (pos - 1 ) else } |
Python3
# character that is repeated def findRepeatFirstN2(s): # this is O(N^2) method for i in range ( len (s)): for j in range (i + 1 , len (s)): if (s[i] = = s[j]): break if (p ! = - 1 ): if __name__ = = '__main__' : str = 'geeksforgeeks' if (pos = = - 1 ): else : # by ChitraNayal |
C#
// that is repeated { // this is O(N^2) method for (i = 0; i < s.Length; i++) for (j = i + 1; j < s.Length; j++) if (s[i] s[j]) p = i; } if (p != -1) } return p; static public void Main () string str = 'geeksforgeeks' ; Console.WriteLine( 'Not found' ); Console.WriteLine( str[pos]); } // This code is contributed by anuj_67. |
C Program To Count Repeated Character In A String
PHP
// PHP program to find the fist { $p = -1; { $j < strlen ( $s ); $j ++) if ( $s [ $i ] $s [ $j ]) $p = $i ; } if ( $p != -1) } return $p ; $str = 'geeksforgeeks' ; echo ( 'Not found' ); echo ( $str [ $pos ]); // This code is contributed by jit_t |
Output:
![C Program To Count Repeated Character In A String C Program To Count Repeated Character In A String](/uploads/1/3/3/2/133279724/827002408.jpg)
Optimization by counting occurrences
This solution is optimized by using the following techniques:
1. We loop through the string and hash the characters using ASCII codes. Store 1 if found and store 2 if found again. Also, store the position of the letter first found in.
1. We loop through the string and hash the characters using ASCII codes. Store 1 if found and store 2 if found again. Also, store the position of the letter first found in.
2. We run a loop on the hash array and now we find the minimum position of any character repeated.
Captain tsubasa 1983 dubbing indonesia. This will have a runtime of O(N).
C++
// is repeated // 256 is taken just to ensure nothing is left, #define MAX_CHAR 256 int findRepeatFirst( char * s) // this is optimized method // elements as zero int pos[MAX_CHAR]; for (i = 0; i < strlen (s); i++) { if (hash[k] 0) { pos[k] = i; hash[k]++; if (hash[i] 2) { p = pos[i]; p = pos[i]; } return p; int main() char str[] = 'geeksforgeeks' ; if (pos -1) else return 0; // by Akanksha Rai |
C
// is repeated #include <string.h> // 256 is taken just to ensure nothing is left, #define MAX_CHAR 256 int findRepeatFirst( char * s) // this is optimized method // elements as zero int pos[MAX_CHAR]; for (i = 0; i < strlen (s); i++) { if (hash[k] 0) { pos[k] = i; hash[k]++; if (hash[i] 2) { p = pos[i]; p = pos[i]; } return p; int main() char str[] = 'geeksforgeeks' ; if (pos -1) else return 0; |
Java
// that is repeated import java.util.*; { { int p = - 1 , i, k; // initialized counts of occurrences of int MAX_CHAR = 256 ; int pos[] = new int [MAX_CHAR]; for (i = 0 ; i < s.length(); i++) k = ( int )s.charAt(i); { pos[k] = i; else if (hash[k] 1 ) } for (i = 0 ; i < MAX_CHAR; i++) if (hash[i] 2 ) if (p - 1 ) // base case else if (p > pos[i]) } } // Driver code { int pos = findRepeatFirst(str); System.out.println( 'Not found' ); System.out.println(str.charAt(pos)); } // Code Contributed by Mohit Gupta_OMG |
Python3
# character that is repeated # 256 is taken just to ensure nothing p = - 1 # initialized counts of occurrences hash = [ 0 for i in range (MAX_CHAR)] # initialized positions k = ord (s[i]) hash [k] + = 1 elif ( hash [k] = = 1 ): if ( hash [i] = = 2 ): p = pos[i] p = pos[i] if __name__ = = '__main__' : pos = findRepeatFirst( str ); print ( 'Not found' ) print ( str [pos]) # This code is contributed by |
C#
// that is repeated public class GFG public static int findRepeatFirst( string s) // this is optimized method // elements as zero int []hash = new int [MAX_CHAR]; // initialized positions { if (hash[k] 0) hash[k]++; } hash[k]++; { { p = pos[i]; p = pos[i]; } return p; public static void Main() string str = 'geeksforgeeks' ; if (pos -1) else } |
Output:
More optimized SolutionRepeated Character Whose First Appearance is Leftmost
C Program To Count Number Of Same Characters In A String
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Improved By : nitin mittal, vt_m, jit_t, Akanksha_Rai, Ita_c, more